Another Math Teaser

Yesterday’s Problem:

There are 10 cargs in a blag, 6 blags in a shrip, 5 shrips in a flirp, and 7 flirps in a trog. What is the number of cargs in a trog divided by the number of blags in a flirp?

Answer:

70

1 blag = 10cargs, 1shrip = 6blags so => 6blag X 10carg = 60carg in a shrip
1flirp = 5shrip => 5 X 60ccarg = 300carg in a shrip
1trog = 7flirp => 7 X 300carg = 2100carg in a trog
2100 cargs in a trog. 1 flirp = 300carg = 30 X 10carg = 30 blags, so there are 30 blags in a flirp
2100 / 30 = 70

Today’s Problem:

What number is 4 times 1/10 the number that is 1/10 less than 3/13?

How Many?

Last Problem:

What is the next letter in this sequence?

W,I,T,N,L,I,T, ?

Answer:

See  the first letters of the words in the question: What Is The Next Letter In This Sequence

Today’s Problem:

There are 10 cargs in a blag, 6 blags in a shrip, 5 shrips in a flirp, and 7 flirps in a trog. What is the number of cargs in a trog divided by the number of blags in a flirp?

Roman Numerals

Yesterday’s Problem:

Which word is different from the others in this list:

cigar, calmer, sorbet, wined, beeches

Answer:

“beeches” – the other words can be rearranged into known boy’s names: cigar=>Craig, calmer=>Marcel, sorbet=>Osbert, wined=>Edwin. Beeches doesn’t rearrange into a known boy’s name

Today’s Problem:

You know how to use Roman numerals.

If we write CXV = SIX and CMLMI = SEVEN, what is LMXI?