Last Problem:
One grandfather, one grandmother, two fathers, two mothers, four children, three grandchildren, one brother, two sisters, two sons, two daughters, one father-in-law, one mother-in-law and one daughter-in-law attended a family reunion. If both halves of each relationship attended (i.e., the father and the son), how many people showed up?
Answer:
There were seven people at the reunion: a man and his wife, their three children (two girls and a boy) and the man’s mother and father.
Without stipulation that both halves of the relationships were present, there could be as few as four people. After all, one man can simultaneously be a father, a grandfather, a son, a brother and a father-in-law.
Today’s Problem:
Three nickels and three dimes are distributed among three piggy banks such that each piggy bank holds two coins. One piggy bank has a label of 20 cents. One bank has a label of 15 cents. And, one bank has a label pf 10 cents.
There is a problem. Although each bank has a label showing how much money is supposed to be found in each piggy bank respectively, all three piggy banks are mislabeled.
Is it possible to determine how to correctly re-label the banks simply by shaking one of the banks until one of the coins drops out? If so, how could this be possible?